________________________________
From: ankur aggarwal <ankur.mast....@gmail.com>
To: algogeeks@googlegroups.com
Sent: Tuesday, 8 September, 2009 9:02:45 PM
Subject: [algogeeks] Re: n balls having k colors
int num_balls[K] = {0}; // one entry per color.
Use num_balls[] to count balls for each color. Now we just need to permute
num_balls[].
"sort balls[] on the basis of code[color_tag]"
wat r u doing here ??
Well for what its worth, here I am sorting balls[] array such that instead of
comparing balls[i] < balls[j], I am comparing, code[color(balls[i])] <
code[color(balls[j])].
On Tue, Sep 8, 2009 at 8:35 PM, manish bhatia <mb_mani...@yahoo.com> wrote:
Assign 0 to K numbers to all K colors, such that color -> color_tag (a number
b/w [0,K-1]).
>code[k] = {0,2,..,k-1}
>foreach (permutation from all possible-permuations of code[])
> sort balls[] on the basis of code[color_tag]
> print balls[]
>
>
>
________________________________
From: ankur aggarwal <ankur.mast....@gmail.com>
>To: lets-talk-g...@googlegroups.com; algogeeks@googlegroups.com
>Sent: Sunday, 6 September, 2009 1:36:01 PM
>Subject: [algogeeks] n balls having k colors
>
>
>You have N balls having one of K colors. Arrange them into groups of same
>colors. e.g.
>
>RRRRRRGRG
>can be arranged as
>RRRRRRRGG (Answer)
>GGRRRRRRR
>
>
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>
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@manish
wat is the complexity ??
think about it...
Yeah complexity is way off! Perhaps we can do the following (provided we can
use extra space).
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