Computing log base 2 is one multiplication simpler than computing log
base 3.

Dave

On Sep 22, 7:49 pm, Prabhu Hari Dhanapal <dragonzsn...@gmail.com>
wrote:
> is computing  log to the  base 2  simpler than  computing log to the  base 3
> ?
>
>
>
>
>
> On Tue, Sep 22, 2009 at 5:40 PM, Dave <dave_and_da...@juno.com> wrote:
>
> > He didn't ask for efficient ways, only other ways.
>
> > On Sep 22, 2:36 pm, Ramaswamy R <ramaswam...@gmail.com> wrote:
> > > Can we evaluate the logarithm any more efficiently that repeated division
> > by
> > > 3?
>
> > > On Tue, Sep 22, 2009 at 12:27 PM, Dave <dave_and_da...@juno.com> wrote:
>
> > > > You could compute the logarithm of the number to the base 3 and see if
> > > > the result is an integer.
>
> > > > Dave
>
> > > > On Sep 21, 12:22 pm, Anshya Aggarwal <anshya.aggar...@gmail.com>
> > > > wrote:
> > > > > how to find that whether the given number was of the form 3^n. ( i.e.
> > 3
> > > > to
> > > > > the power n).
> > > > > one way is to recursively divide the number by 3 and check the
> > remainder.
> > > > > Is there any other way using bit manipulation or anything else??
>
> > > > > --
> > > > > Anshya Aggarwal
>
> > > --
> > > Yesterday is History.
> > > Tomorrow is a Mystery.
> > > Today is a Gift! That is why it is called the Present :).
>
> > >http://sites.google.com/site/ramaswamyr-Hide quoted text -
>
> > > - Show quoted text -
>
> --
> Hari- Hide quoted text -
>
> - Show quoted text -
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