It will take n comparisons.....observe this code....
#include<iostream> using namespace std; int sec_largest(int ar[],int n) { int i,max=-32767,sec_max=0; for(i=0;i<n;i++) { if(ar[i]>max) { sec_max=max; max=ar[i]; } } return sec_max; } main() { int n,i,res; cout<<"enter number of elements\n"; cin>>n; int ar[n]; for(i=0;i<n;i++) cin>>ar[i]; res=sec_largest(ar,n); cout<<"second largest number="<<res<<endl; } --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/algogeeks -~----------~----~----~----~------~----~------~--~---