no need to take care of negative numbers because given number is unsigned
long integer ......
apply simple algo :)
On Thu, Oct 15, 2009 at 1:07 PM, Siddharth S <mitsiddha...@gmail.com> wrote:
>
> void putlong(long n)
> {
> if(n == 0) // special case
> {
> putchar('0');
> return;
> }
> else
> if(n < 0) // if number is negative, print "-" sign and continue as if it
> is a positive number
> putchar('-'), n = -n;
>
> int arr[30];
> int arr_cnt = 0;
> while(n)
> {
> arr[arr_cnt++] = n % 10; // split number into digits
> n /= 10;
> }
> for(int i = arr_cnt-1; i>=0; i--) // print the digits (in reverse order)
> putchar(arr[i]+'0');
> }
>
> On Thu, Oct 15, 2009 at 9:33 AM, ankur aggarwal
> <ankur.mast....@gmail.com>wrote:
>
>> 1. Given only putchar (no sprintf, itoa, etc.) write a routine
>> putlong that prints out an unsigned long in decimal.
>>
>>
>>
>
> >
>
--
Thanks & Regards
Umesh kewat
Sent from Hyderabad, AP, India
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