People, try this one:
"You and your opponent shall play a game with three dice: First, your
opponent chooses one of the three dice. Next, you choose one of the
remaining two dice. The player who throws the higher number with their
chosen dice wins. Now, each dice has three distinct numbers between 1
and 9, with pairs of opposite faces being identical. Design the three
dice such that you always win! In other words, no matter which dice
your opponent chooses, one of two remaining dice throws a number
larger than your opponent, on average."

I thought. I saw the solution. And I have no clue what the solution
talks about. Can somebody solve it? or re-state the solution in simple
English?

Thanks


[original at: 
http://gurmeetsingh.wordpress.com/2008/11/05/puzzle-non-transitive-dice/

I know I shouldn't be copy-pasting like this. But the puzzle is too
good]

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