void PrintFamilyTree(const short& generation)
{
  printf("Name : %s Generation = %d\n", m_Name.c_str(),generation);

  vector<Human*>::iterator it;

  for (it = this.begin(); it< this.end() ;it++)
  {
     it->PrintFamilyTree(generation+1);
  }
}


On Tue, Nov 24, 2009 at 9:20 PM, Aditya Shankar <
iitm.adityashan...@gmail.com> wrote:

>
> Hi,
>
> On Tue, Nov 24, 2009 at 6:38 PM, Ankur <ankuraror...@gmail.com> wrote:
>
>> What would be the best algorithm for the undermentioned problem.
>>
>> Implement method PrintFamilyTree() that prints out the Name and
>> Generation of the tree
>> Output should resemble
>> Name: Jan Generation:0
>> Name: Mike Generation:1
>> Name: Greg Generation:2
>> Name: Carol: Generation: 2
>> Name: Peter Generation: 3
>> Name: Marcia Generation: 3
>> Name: Bobby Generation: 1
>>
>>     The order you have mentioned is preorder traversal of the tree.
>
> Regards
> Aditya Shankar
>
>> class Human : public std::vector<Human *>
>> {
>> public:
>> Human(const std::string &name) : m_Name(name) {};
>> virtual void PrintFamilyTree(const short &generation = 0) const;
>> protected:
>> std::string m_Name;
>> };
>>
>> class Male: public Human
>> {
>> public:
>> Male(const std::string &name) : Human(name) {};
>> };
>>
>> class Female: public Human
>> {
>> public:
>> Female(const std::string &name) : Human(name) {};
>> };
>>
>> void main()
>> {
>> Male m1("Mike"), m2("Greg"), m3("Peter"), m4("Bobby");
>> Female f1("Carol"), f2("Marcia"), f3("Jan");
>>
>> m1.push_back(&m2);
>> f1.push_back(&m3);
>> f1.push_back(&f2);
>> m1.push_back(&f1);
>> f3.push_back(&m1);
>> f3.push_back(&m4);
>>
>> f3.PrintFamilyTree();
>>
>> --
>>
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