Same applies for this too.

1 2 3
3 5 6
4 7 8

After bsearch on diagonal you are left with (5,6 and 5,7). Do bsearch on
this.

On Wed, Nov 25, 2009 at 6:27 PM, Bharath <bharath1...@gmail.com> wrote:

> Bsearch on diagonal elimanates all the submatrix under 9.
>
> You are left with only one column and a row.Do BinarySearch on these lists.
>
>
> On Wed, Nov 25, 2009 at 6:07 PM, chitta koushik <
> koushik.infin...@gmail.com> wrote:
>
>> @Bharath
>>
>> I dont think BinSrch on diagnol and then on row works.
>> Can u explain your algo?  chk for this matrix
>>
>> 1  2  3  4  5
>> 2  9 12 19 24
>> 3  10 14 18 20
>> 8  13 15 20 23
>> 11 14 16 21 24
>>
>> Find(8) doesn't give o/p
>>
>>
>> --Koushik C
>>
>> On Wed, Nov 25, 2009 at 5:18 PM, Arun <arunm...@gmail.com> wrote:
>>
>>> how about splitting the matrix into 4 squares and considering the
>>> rightmost bottom and comparing it to topmost left corner of each square. in
>>> every iteration you will eliminate atleast one square. so worst case, you
>>> have to repeat this divide and conquer on the three other squares.
>>> not good as as binary search though(in the sense of eliminating 2
>>> squares).
>>>
>>> On Wed, Nov 25, 2009 at 3:12 AM, Aditya Shankar <
>>> iitm.adityashan...@gmail.com> wrote:
>>>
>>>>
>>>>
>>>> On Wed, Nov 25, 2009 at 2:16 PM, Bharath <bharath1...@gmail.com> wrote:
>>>>
>>>>> You can actually do it in O(logn) complexity. Binary Search on diagonal
>>>>> and then on a row.
>>>>
>>>> Will that always work?
>>>> 1 2 3
>>>> 3 5 6
>>>> 4 7 8
>>>>
>>>> Find(6) fails with the usual binary search algorithm.
>>>>
>>>>
>>>>>
>>>>>
>>>>> On Tue, Nov 24, 2009 at 10:33 PM, chitta koushik <
>>>>> koushik.infin...@gmail.com> wrote:
>>>>>
>>>>>> Start from top right or bottom left corner and move according if the
>>>>>> element to be searched is lesser or greater than current.
>>>>>>
>>>>>>
>>>>>> --Koushik C
>>>>>> Pablo 
>>>>>> Picasso<http://www.brainyquote.com/quotes/authors/p/pablo_picasso.html> 
>>>>>> - "Computers are useless. They can only give you answers."
>>>>>>
>>>>>>
>>>>>> On Tue, Nov 24, 2009 at 7:27 PM, Rohit Saraf <
>>>>>> rohit.kumar.sa...@gmail.com> wrote:
>>>>>>
>>>>>>> A nice problem that i encountered :
>>>>>>> In O(n) search for a value x in a sorted NxN matrix.
>>>>>>> Definition of sorted matrix:  All rows and all columns are sorted in
>>>>>>> ascending order.
>>>>>>>
>>>>>>>  So thought of sharing ..
>>>>>>>
>>>>>>>
>>>>>>> Rohit Saraf
>>>>>>> Sophomore
>>>>>>> Computer Science and Engineering
>>>>>>> IIT Bombay
>>>>>>>
>>>>>>> --
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>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> <<Bharath>>
>>>>>
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>
>
> --
> <<Bharath>>
>
>


-- 
<<Bharath>>

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