copy the array(A) in a different array(B) to store the index info.(space O(n)) sort(A) take each pair's sum ( complexity O(n^2) ) and with that do a binary search for the 3rd element needed.(O(log(n))).
Check for the indices in B. i believe it can be done in better time somehow. On Mon, May 3, 2010 at 6:48 PM, jalaj jaiswal <jalaj.jaiswa...@gmail.com>wrote: > > given an array(unsorted) may contain negative numbers too > find the index of three numbers whose sum is closest to zero in O(N2 log > N) time and O(N) space. > > P.S -3 is more close to zero then -6 (number line ...) > -- > With Regards, > Jalaj Jaiswal > +919026283397 > B.TECH IT > IIIT ALLAHABAD > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algoge...@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com> > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
