thanks a lot to all for their replies..

On 9 May 2010 11:23, rahul rai <raikra...@gmail.com> wrote:

> can anyone give me links to more educative and active groups like algogeeks
>
> On Sun, May 9, 2010 at 2:11 AM, Arun prasath
> <aruntendulkar2...@gmail.com> wrote:
> > This does not create a balanced tree but ensures that every element in
> the
> > tree is accessible by lg(n) time.
> >
> > Time : Complexity   O(n)
> >
> >
> > [a...@91blore-srv1 ~]$ cat recursion.c
> > #include <stdlib.h>
> > #include<unistd.h>
> > #include <stdio.h>
> > #define TEST2
> > #ifdef TEST1
> > int arr[] = { 1,2,3,4,5,6,7};
> > int max_elems = sizeof(arr)/sizeof(arr[0]);
> > #endif
> >
> > #ifdef TEST2
> > int arr[] = { 1,2,3,4,5};
> > int max_elems = sizeof(arr)/sizeof(arr[0]);
> > #endif
> >
> > #ifdef TEST3
> > int arr[] = { 1,2,3,4,5,6,7,8};
> > int max_elems = sizeof(arr)/sizeof(arr[0]);
> > #endif
> >
> > #define LIST_EMPTY -1
> >
> > struct tree {
> >     int data;
> >     struct tree * left,* right;
> > };
> >
> > struct tree* function( int , int);
> > void print_inorder( struct tree *);
> >
> > int return_next_from_list(void)
> > {
> >     static int nxt_elem = 0;
> >     if(nxt_elem < max_elems)
> >         return arr[nxt_elem++];
> >
> >     return LIST_EMPTY;// empty condition
> > }
> > int main()
> > {
> >     unsigned int  x = max_elems;
> >     struct tree* head;
> >     while( x & (x - 1) ) {
> >         x = x & (x - 1) ;
> >     }
> >
> >     head = function(0, x);
> >     print_inorder(head);
> >     free(head);
> >     return 0;
> > }
> > struct tree* function(int mid, int i)
> > {
> >     int val = mid + i ;
> >     if (val & 1) {
> >         struct tree * leaf = malloc( sizeof(struct tree) );
> >         leaf->left = leaf->right = NULL;
> >         leaf->data = return_next_from_list();
> >         if(leaf->data == LIST_EMPTY) {
> >             free(leaf);
> >             return NULL;
> >         }
> >         return leaf;
> >     }
> >     struct tree *non_leaf = malloc( sizeof(struct tree) ) ;
> >
> >     non_leaf->left  = function( mid, i/2);
> >     non_leaf->data = return_next_from_list();
> >     if (non_leaf->data == LIST_EMPTY) {
> >         struct tree *tmp = non_leaf->left;
> >         free(non_leaf);
> >         return tmp;
> >     }
> >     non_leaf->right = function( mid+i, i/2);
> >     return non_leaf;
> > }
> > void print_inorder( struct tree* root)
> > {
> >     struct tree * trav = root;
> >     if (!trav) {
> >         return;
> >     }
> >     print_inorder(trav->left);
> >     if(trav->left)
> >         free(trav->left);
> >     printf("{%d}", trav->data);
> >     print_inorder(trav->right);
> >     if(trav->right)
> >         free(trav->right);
> >
> > }
> > [a...@91blore-srv1 ~]$
> >
> >
> > On Sun, May 2, 2010 at 6:38 PM, divya <sweetdivya....@gmail.com> wrote:
> >>
> >> u are given a sorted lnked list construct a balanced binary search
> >> tree from it.
> >>
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