The only solution I can think of is to use the binomial theorem (http://en.wikipedia.org/wiki/Binomial_theorem) to expand (3+sqrt(5))^n . Then you only need to take into the account the terms where y (sqrt(5)) has an odd power because all others are integers and won't affect the decimals. Then after adding them up you'll end up with something like n * sqrt(5) where n is the total of the coeficients of sqrt(5) and then just do the math and find out the 3 decimals.
-- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
