http://code.google.com/codejam/contest/dashboard?c=32016#s=a&a=2
2010/5/19 Adrian <kri...@gmail.com> > > The only solution I can think of is to use the binomial theorem > (http://en.wikipedia.org/wiki/Binomial_theorem) to expand > (3+sqrt(5))^n . Then you only need to take into the account the terms > where y (sqrt(5)) has an odd power because all others are integers and > won't affect the decimals. Then after adding them up you'll end up > with something like n * sqrt(5) where n is the total of the > coeficients of sqrt(5) and then just do the math and find out the 3 > decimals. > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algoge...@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com> > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- Mario Ynocente Castro Undergraduate Student of System Engineering National University of Engineering, Peru http://sites.google.com/site/ycmario -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
