As you already mentioned sizeof is an operator and not a lib fn.
Which means it will be evaluated/code for it will be replaced at compile
time rather than during execution.
It will follow the following grammar,
unary_operator: sizeof , and others
sizeof: ( unary expression | type_name)
and so on for unary expression and type_name which would eventually result
in built-in or user-defined data-types whose 'size' can be inferred from
symbol table.
If some one needs to code a size of operator, it won;t be possible since you
can not actually pass type in c, there can be ways to do this using macros
like using stringization of macro.
On Mon, May 31, 2010 at 1:14 PM, debajyotisarma
<sarma.debajy...@gmail.com>wrote:
> This is not about algorithms,but related to C programming.
>
> How to implement sizeof operator?
>
> macro for this
> #define my_sizeof(a) (char*)(&a+1)-(char*)&a
>
> this works fine of variables
> int a;
> printf("%d",my_sizeof(a)); //or even for user defined
> structures
>
> but it will not work for data types
>
> like
>
> printf("%d",my_sizeof(int));
>
> so please get another solution.
> function will be preferable.not macro
>
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