@Antony: The 2 lists should have the same elements as well the number must
be equal

On Wed, Jun 2, 2010 at 5:38 PM, Antony Vincent Pandian.S. <sant...@gmail.com
> wrote:

> @Raj
>
> What do you mean by identical? You are just concerned about the
> presence of one element in another LL or you are concerned about the
> equality of number of elements too?
>
> On 6/2/10, Raj N <rajn...@gmail.com> wrote:
> > @sharad kumar: But don't you think this'll consume a lot of space. Merge
> > sort will give O(nlogn) complexity when a separate LL is used to store
> the
> > sorted elements but if we disbuild the same LL it'll be >O(n2). And also
> wat
> > do u mean by combining LL can u explain
> >
> >
> > On Wed, Jun 2, 2010 at 6:48 AM, sharad kumar <aryansmit3...@gmail.com
> >wrote:
> >
> >> @Raj:sorting can be done in O(nlogn)..sort both and compare both.or use
> a
> >> hash map to store all elements of one LL and then compare it with
> >> other....or combine both the  LL perform merge sort and start deleting
> >> adjacent elements.if adjacent elements in equal count then LL are equal
> >> and
> >> at end of process we get an empty list.....
> >>
> >>
> >> On Tue, Jun 1, 2010 at 11:55 PM, Raj N <rajn...@gmail.com> wrote:
> >>
> >>> Hi all,
> >>> Can someone suggest an efficient algorithm to check if 2 linked lists
> >>> are identical. If 2 lists have to be sorted then there'll be a lot of
> >>> space consumption for 2 separate linked lists. Can the whole process
> >>> be done < O(n2)
> >>>
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> Luv,
> S.Antony Vincent Pandian
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