@Divya: That was the question i previously asked. If n=3 000,001,010,100,101 are valid. So the solution for this is fib(n+2). If n=4 no. of sequences will be fib(6) i.e 8
On Tue, Jun 8, 2010 at 9:31 AM, Rohit Saraf <rohit.kumar.sa...@gmail.com>wrote: > getting fibonacci nos is trivial using matrix multiplication in almost > constant time. > > -------------------------------------------------- > Rohit Saraf > Second Year Undergraduate, > Dept. of Computer Science and Engineering > IIT Bombay > http://www.cse.iitb.ac.in/~rohitfeb14<http://www.cse.iitb.ac.in/%7Erohitfeb14> > > > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algoge...@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com> > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
