@Harish, it does.
@Divya, r we not on the same page.

On Thu, Jun 10, 2010 at 10:20 AM, Harish U <harishs...@gmail.com> wrote:

> @Saurabh
> I believe for Isomorphic trees only the structure counts not the value at
> each nodes.
> So i think there is no need to compare the value at the corresponding node
> positions of the two trees.
>
>
> On Wed, Jun 9, 2010 at 11:15 PM, saurabh gupta <sgup...@gmail.com> wrote:
>
>> is-isomorphic(t1, t2) {
>>      t1ld = t1->left->data
>>      t2ld = t2->left->data
>>     //.....
>>
>>     //base case for null or replace by sentinels and check
>>     if( t1ld == t2ld && t1rd == t2rd)
>>        return is-isomorphic(t1ld, t2ld) && return is-isomorphic(t1rd,
>> t2rd)
>>     if (t1ld == t2rd && t1rd == t2ld)
>>        return is-isomorphic(t1ld, t2rd) && return is-isomorphic(t1rd,
>> t2ld)
>>     return false;
>>
>> }
>>
>> On Wed, Jun 9, 2010 at 8:29 PM, divya jain <sweetdivya....@gmail.com>wrote:
>>
>>> @vadivel and anand
>>>
>>> { 1,2,3 } is *isomorphic* to { 1,3,2 }
>>> { 1,2,3,4,5,6,7 } is *isomorphic* to { 1,3,2,7,6,4,5 }
>>> { 1,2,3,4,5,6,7 } is NOT *isomorphic* to { 1,3,2,4,5,6,7 }
>>>
>>> so its nt necessary that right and left will interchange. it may or may
>>> not. if all right and left are interchanged then it is mirror tree. i think
>>> ur code is for mirror tree and not isomorphic tree..
>>>
>>>
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>>
>>
>>
>> --
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>> vague and uncertain. Doctor says "Treatment is simple. Great clown
>> Pagliacci is in town tonight. Go and see him. That should pick you up."
>> Man
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-- 
Man goes to doctor. Says he's depressed. Says life seems harsh and cruel.
Says he feels all alone in a threatening world where what lies ahead is
vague and uncertain. Doctor says "Treatment is simple. Great clown
Pagliacci is in town tonight. Go and see him. That should pick you up." Man
bursts into tears. Says "But, doctor...I am Pagliacci."

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