I guess it can be done in efficiently using a simple divide and conquer
scheme almost imitating mergesort.
Can you think of it now? :D

--------------------------------------------------
Rohit Saraf
Second Year Undergraduate,
Dept. of Computer Science and Engineering
IIT Bombay
http://www.cse.iitb.ac.in/~rohitfeb14


On Fri, Jun 11, 2010 at 10:07 PM, sharad kumar <sharad20073...@gmail.com>wrote:

> all possible pairs
>
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