111
222
333
344
ptr++ ->u do posst increment
hence it goes to 1
ptr-p=*(&(arr+1)-&arr)=1
llrly for other cases
when u do *ptr++ due to operator precedence ptr++ is done and then
dereferenced.
hence u get 222
next *++ptr
the ptr is incremented after dereferencing hence u get 333
next ++*ptr here the value t ptr s incrementas it is treated as++(*ptr)
hence u get 3 but others refer to location hence 44
On Sat, Jun 12, 2010 at 9:21 PM, divya <sweetdivya....@gmail.com> wrote:
> #include<stdio.h>
> int main()
> {
> static int arr[]={0,1,2,3,4};
> int *p[]={arr,arr+1,arr+2,arr+3,arr+4};
> int **ptr=p;
> ptr++;
> printf("%d %d %d\n",ptr-p,*ptr-arr,**ptr);
> *ptr++;
> printf("%d %d %d\n",ptr-p,*ptr-arr,**ptr);
> *++ptr;
> printf("%d %d %d\n",ptr-p,*ptr-arr,**ptr);
> ++*ptr;
> printf("%d %d %d\n",ptr-p,*ptr-arr,**ptr);
> return 0;
> }
> wat shd b the o/p n why...
>
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