@^ he has already asked to optimize n^2logn solution On Wed, Jun 16, 2010 at 5:25 PM, divya jain <sweetdivya....@gmail.com>wrote:
> sort array c only. > now select every pair from array a nd b ( o(n2)) > for every pair find the element from c which gives sum of the three element > 0. ( search using binary search as c is sorted) > so the algo is O (n^2 logn)) > > > On 16 June 2010 13:47, Amir hossein Shahriari < > amir.hossein.shahri...@gmail.com> wrote: > >> @algoose chase: you're right thx for the test case >> >> On Wed, Jun 16, 2010 at 11:45 AM, Algoose Chase <harishp...@gmail.com>wrote: >> >>> @ Amir: >>> I think you cannot find two numbers in B and C such that their sum is >>> -A[k] in O(n) in all cases with the logic that you mentioned. >>> >>> for instance you can try with : >>> A : 2 7 8 10 >>> B :-2, 0, 1, 9 >>> C: -7 -2 1 3 >>> >>> On Wed, Jun 16, 2010 at 5:56 AM, Amir hossein Shahriari < >>> amir.hossein.shahri...@gmail.com> wrote: >>> >>>> sort all arrays >>>> for each number in A , A[k] >>>> find two numbers in B and C such that their sum is -A[k] >>>> this can be done in O(n) time: >>>> >>>> set i at the beginning of B and j at the end of C >>>> while i<n or j>=0 >>>> if ( B[i] + C[j] == -A[k] ) return true >>>> if ( B[i] + C[j] < -A[k] ) increase i >>>> else decrease j >>>> >>>> we have to do this for each element of A so the overall complexity is: >>>> O(n2) time O(1) space >>>> >>>> correct me if I'm wrong >>>> >>>> On 6/15/10, sharad kumar <sharad20073...@gmail.com> wrote: >>>> > plzzz comment on this question >>>> > >>>> > -- >>>> > You received this message because you are subscribed to the Google >>>> Groups >>>> > "Algorithm Geeks" group. >>>> > To post to this group, send email to algoge...@googlegroups.com. >>>> > To unsubscribe from this group, send email to >>>> > algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com> >>>> . >>>> > For more options, visit this group at >>>> > http://groups.google.com/group/algogeeks?hl=en. >>>> > >>>> > >>>> >>>> -- >>>> You received this message because you are subscribed to the Google >>>> Groups "Algorithm Geeks" group. >>>> To post to this group, send email to algoge...@googlegroups.com. >>>> To unsubscribe from this group, send email to >>>> algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com> >>>> . >>>> For more options, visit this group at >>>> http://groups.google.com/group/algogeeks?hl=en. >>>> >>>> >>> -- >>> You received this message because you are subscribed to the Google Groups >>> "Algorithm Geeks" group. >>> To post to this group, send email to algoge...@googlegroups.com. >>> To unsubscribe from this group, send email to >>> algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com> >>> . >>> For more options, visit this group at >>> http://groups.google.com/group/algogeeks?hl=en. >>> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algoge...@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com> >> . >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algoge...@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com> > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- With Regards, Jalaj Jaiswal +919026283397 B.TECH IT IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
