Here is a simple Implementation for it.
http://codepad.org/6TPw3txq
On Tue, Jun 15, 2010 at 6:06 AM, Anurag Sharma <anuragvic...@gmail.com>wrote:
> just check the signs of the i, j components of vector from the centre of
> screen to (x,y)
>
> pseudo code:-
> getQuadrant(x,y){
> string Q[]={"1st","4th","2nd", "3rd"};
> vx=(x>=midx)?0:1
> vy=(y>=midy)?0:1
> return Q[(vx<<1)|vy]
> }
>
> Anurag Sharma
>
>
>
> On Mon, Jun 14, 2010 at 5:55 PM, siddharth srivastava <akssps...@gmail.com
> > wrote:
>
>> I have this code snippet:
>> This code snippet defines a boundary coordinates on the screen wrt to the
>> center(of the screen).
>>
>> if( x < x_center )
>> x_border = x_center - x_shift;
>> else
>> x_border = x_center + x_shift;
>>
>> if( y < y_center )
>> y_border = y_center - y_shift;
>> else
>> y_border = y_center + y_shift;
>>
>> //x_shift and y_shift are constants.
>>
>> What is the best possible way to determine in which quadrant( wrt to the
>> center) the point (x,y) lies ?
>>
>>
>> Siddharth Srivastava
>>
>>
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