your question is very similar to this acm problem:
http://www.acmgnyr.org/year2009/e.pdf
and my approach was to find the number of characters at the end of string
that are sorted decreasingly e.g. in "abcgda" the length of such sub-string
is 3 ( "gda" ) then look at the next char (here it is 'c' ) this character
must be replaced with the smallest character in the decreasing sub-sequence
which is bigger than this char (here it's 'd') then sort the decreasing
sub-string to be increasing
so the next lexicographical string of "abcgda" is "abdacg" ('d' is replaced
with 'c' and then "gca" is sorted to be "acg")
note that if a string is sorted decreasingly like "dcba" it's next char does
not exist so it's next string doesn't exist
On Mon, Jun 21, 2010 at 6:55 PM, nisha goyal <nisha.goyal1...@gmail.com>wrote:
> i think if we just reverse the last two alphabets of the string then also
> it will the next lexicographic string having the same alphabets.
>
> any comments??
>
>
> On 6/21/10, sharad kumar <sharad20073...@gmail.com> wrote:
>>
>> is this approach works
>> 1. write the post order traversal of T1 and T2 and save it in strings P1
>> and P2.
>> 2. similarly write the In order traversal of T1 and T2, saving it in
>> strings I1 and I2.
>> 3. if T1 contains T2, then P1 contains P2 and I1 contains I2 as
>> substrings.
>>
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