Here is the code in Java:
public class distanceOfStrings {
public static void main(String args[]){
String s1 ="abcd";
String s2 ="abcde";
char[] as1 = s1.toCharArray();
char[] as2 = s2.toCharArray();
int s1Len = s1.length();
int s2Len = s2.length();
int j=0;
int diff = 0;
if ( s1Len-s2Len > 1 || s2Len-s1Len > 1 ){
System.out.println("Two strings are not at a distance of 1");
return;
}
if (s1Len != s2Len ) {
for (int i=0; i<s1Len && j<s2Len;) {
if (as1[i] == as2[j]) {
i++; j++;
}
else if (diff == 0 && s1Len > s2Len ) {
diff = 1;
i++;
}
else if (diff == 0 && s1Len < s2Len) {
diff = 1;
j++;
}
else {
diff = 2;
System.out.println("Two strings are not at a distance of 1");
return;
}
}
}
else {
for (int i=0; i<s1Len && j<s2Len;) {
if (as1[i] == as2[j]) {
i++; j++;
}
else if (diff == 0) {
diff = 1;
i++;j++;
}
else {
diff = 2;
System.out.println("Two strings are not at a distance of 1");
return;
}
}
}
System.out.println("Yep..Two strings are at a distance of 1");
}
}
--------------------------------
On Sun, Jun 20, 2010 at 4:10 PM, sharad <sharad20073...@gmail.com> wrote:
> Write a code which will find whether two strings are at a distance of
> 1. Distance of 1 meaning that they differ by the insertion/deletion or
> replacement of 1 char. For e.g.
> s1 -> abcd
> s2->acd
>
> s1-> abcd
> s2-> ascd
>
> s1->abcd
> s2->abcde
>
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--
cheers
Jeeva
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