Hi Raj,

What if the boxes are given in some different order. The solution given
depends very much on the order in which boxes are given.

On Wed, Jun 23, 2010 at 2:10 PM, Raj N <rajn...@gmail.com> wrote:

> Given a lot of cuboid boxes with different length, breadth and height.
> We need to find the maximum subset which can fit into each other.
>
> For example:
> If Box 1 has LBH as 7 8 9
> If Box 2 has LBH as 5 6 8
> If Box 3 has LBH as 5 8 7
> If Box 4 has LBH as 4 4 4
>
> then answer is 1,2,4
>
> A box can fit into another only and only if all dimensions of that is
> less than the bigger box.Rotation of boxes is not possible.
>
> My approach:
>
> Constructing trees...
> Box 1 dim: 7,8,9 Make it as root1. The root also has a counter
> associated with it. Now count1=1.
> Then Box 2 dim: 5,6,8 < 7,8,9. Make it as a left child of root1 and
> count1=2.
> Box 3 dim: 5,8,7 doesn't fit in any and hence make it a tree by itself
> i.e root2 its count2=1.
> Box 4 dim: 4,4,4 it can be made as the left child of box 2 as well as
> Box 3.
> count1=3, count2=2.
> Print the reverse inorder traversal of the highest counter valued
> tree.
>
> Please correct me if I'm wrong.
>
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-- 
Regards
Bhanu
Mobile   +91 9886738496

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