#include<iostream>
using namespace std;
int main()
{
int arry[5]={0,1,3,0,4};
int i=0,j=0,k=0;
for(;k<5;++k)
{
if((i==j)&&(arry[i]!=0))
{
++i;
++j;
}
else if(i==j){
j++;
}
else if(arry[j]==0){
j++;
}
else if((arry[i] == 0) && (arry[j]!=0))
{
int tmp;
tmp = arry[j];
arry[j]=arry[i];
arry[i]=tmp;
i++;
j++;
}
}
for(i=0;i<5;++i)
cout<<i;
cin.sync();
cin.get();
return 0;
}
On Sun, Jun 27, 2010 at 1:57 AM, jalaj jaiswal <jalaj.jaiswa...@gmail.com>wrote:
>
> Given an array of integers, {1,0,2,0,3,0,0,4,5,6,7,0,0,0}, you have to
> create a new array which will be like (1,2,3,4,5,6,7,0,0,0,0,0,0,0}, without
> using any other temporary array.
>
>
> --
> With Regards,
> Jalaj Jaiswal
> +919026283397
> B.TECH IT
> IIIT ALLAHABAD
>
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