Hey Priyanka..
Both code are same here u induse temp variable and using later to assign it
with a,
so shrinivas code is right and its working fine... in code value of a is
being used in smart way..
a= a^b
if we again do ex-oring a with b den we will get a orignal value.
a = a^b
suppose value of a= 3 and b = 1 then a =2(a = a^b ) but after we again do
ex-oring then a = 3(a = a^b )
a = 3 = 011
b= 1 = 001 after exroing
-------------------
a = 2 =010 (a = a^b)
b=1 = 001
-----------------
a = 3 = 011 (that value being used in that expression of shrinivas code
b=(a^b)&b; in place of bracket.
--
Thanks & Regards
Umesh kewat
On Thu, Jul 1, 2010 at 8:55 AM, Priyanka Chatterjee <dona.1...@gmail.com>wrote:
> @shrinivas : your iterative code is wrong
>
> It should be:
>
>>
>> int add(int a, int b)
>> { int temp;
>> do
>> {
>> temp=a^b;
>> b=a&b;
>> b=b<<1;
>>
> a=temp;
>
>> } while(b);
>>
>> return(a);
>> }
>>
>>
>> it is working well for negative numbers also . i tried lot but can not
>> understand logic behind it can any one explain it in easy manner ...
>> thanks in advance
>>
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>
>
> --
> Thanks & Regards,
> Priyanka Chatterjee
> Final Year Undergraduate Student,
> Computer Science & Engineering,
> National Institute Of Technology,Durgapur
> India
> http://priyanka-nit.blogspot.com/
>
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