Hi Gaurav,

yup solution is quite right but that is the worst case....but if wanna that
solution in O(n) time complexity and O(1) space complexity but in ur
solution it is O(k)  space complexity.


On Wed, Jul 7, 2010 at 7:17 AM, Gaurav Singh <gogi.no...@gmail.com> wrote:

> I think you can use counting array in this algo. And keep checking
> whenever the count of any element goes ahead of 1, it will be the
> first repeating element.
> Is it something more difficult than this ?? Please correct me if
> anything is wrong in my thought.
>
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Thanks & Regards

Umesh kewat

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