@Anand: it depends on how you think of i i thought of it as the starting digit of a group but you're thinking of it as it's last however both views are correct here since you're talking about my solution minus 2! you need to initialize the dp to 0 (and a bit change in IFs so that you don't refer to a negative index in a[] ) but for my solution (after changing the init value of i to n-2) setting dp[n-1]=dp[n]=dp[n+1]=0 would be enough
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