Let me elaborate,please refer the below diagram, FBH is corner of
inner square and CAD is of the outer square.:
A ____D__
|\ /
| \e
|/_ \B_____H
C| |
| |
F
CD, EB is the proposed position of the planks, i.e. CD is one plank,
EB is another.
BC = L (distance as given), therefore AB = L(sqrt(2))
So. Ae + eB >= L(sqrt(2))
Since Possible MAX(eB) = L (length of the plank),
Ae >= L(sqrt(2)) - L = 0.414 L, apprx.
If I use full length of the plank as L in CD, then Ae comes out to be
0.5L, which satisfies the above. Thus, the solution is feasible. I
hope i have not made it too complicated.
On Jul 20, 8:06 am, Ashish Goel <ashg...@gmail.com> wrote:
> can you show it diagrammatically
>
> is the block square with side L or is it a plank of length L?
>
> putting a plank of lenght L at the corner of square implies that the corner
> side is L/sqrt(2) and the perpendicular falling onto this diagnal plank
> would eat up (sqrt(3)/sqrt(2))L
>
> so left over (ABCD is inner rectangle, and DEFG is outer than i am trying to
> connect AD which is sqrt(2)L
>
> is (sqrt(2)L-sqrt(3)/sqrt(2))L >0
> yes, so i would need essentially minimum 2 planks.
>
> | |_
> |\/
> |_\_
>
> Best Regards
> Ashish Goel
> "Think positive and find fuel in failure"
> +919985813081
> +919966006652
>
> On Tue, Jul 20, 2010 at 12:08 AM, Snoopy Me <thesnoop...@gmail.com> wrote:
> > Nice way to put it erappy, here is another way.
>
> > A block of length L can be place at the corner of the outer square
> > such that it makes a triangle so that two sides of the triangle is the
> > corner sides of the square and the base of the triangle is the block.
> > Now, on this block another block can be placed to reach the corner of
> > the inner square.
>
> > On Jul 19, 10:08 am, erappy <era...@gmail.com> wrote:
> > > Use the block of size L, use the diagonal of the block (diagonal would be
> > > definitely > L ) to fit in between two square islands.
>
> > > Thanks,
>
> > > On Sun, Jul 18, 2010 at 11:38 PM, amit <amitjaspal...@gmail.com> wrote:
> > > > Puzzle, A square Island surrounded by bigger square, and in between
> > > > there is infinite depth water. The distance between them is L. The
> > > > wooden blocks of L are given.
> > > > The L length block can't be placed in between to cross it, as it will
> > > > fall in water (just fitting).
> > > > How would you cross using these L length blocks.
>
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