@Avik: Correcting/augmenting your post: N = (3*4096+15*256+3*16+3) = 3*(2^12) + 15*(2^8) + 3*(2^4) + 3*(2^0) = (2+1)*(2^12) + (8+4+2+1)*(2^8) + (2+1)*(2^4) + (2+1) = (2^1+2^0)*(2^12) + (2^3+2^2+2^1+2^0)*(2^8) + (2^1+2^0)*(2^4) + (2^1+2^0) = 2^13 + 2^12 + 2^11 + 2^10 + 2^9 + 2^8 + 2^5 + 2^4+ 2^1 + 2^0
So there are 10 1's in the binary representation of the number N. Dave On Aug 6, 12:42 am, Avik Mitra <tutai...@gmail.com> wrote: > N = (3*4096+15*256+3*16+3) > = 3* (2^10) + 15*( 2^8) + 3*(2^4) + 3* (2^0) > = (1+2)*(2^10) + (1+2+2^2+ 2^3)*(2^8) + (1+2)*(2^4) + (1+2) > = (2^10 + 2^11) + (2^8+2^9+2^10+2^11) + (2^4 + 2^6)+ (1+2) > = 2^11+2^12+2^8+2^9+2^4+2^6+2+1 > = 1 + 2 + 2^4 + 2^6 + 2^8 + 2^9 + 2^11 + 2^12 > > So there are 8 1's in the binary representation of the number N. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
