On Monday 09 August 2010 13:22:20 Avik Mitra wrote: > ANSI standard specifies that during right shift of a negative number > the shift MUST be a logical shift with sign extension. So, 1111 1111 > 1111 1111 when right shifted will logically with sign extention it > gives FFFF (in hex). > So the answer is [A].
Dave is right. Quoting from C99 (the _current_ ANSI C standard): "The result of E1 >> E2 is E1 right-shifted E2 bit positions. If E1 has an unsigned type or if E1 has a signed type and a nonnegative value, the value of the result is the integral part of the quotient of E1 / 2^E2 . If E1 has a signed type and a negative value, the resulting value is implementation-defined." -- Mihai Donțu -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
