we can merge the 2 arrays in sorted manner. Now from the 2nd last number,we
can have the first pair (last,second last).From the 3rd last,we can have 2
pairs (last,3rd last) and (2nd last,3rd last). similarly we will keep on
taking till we get n pairs.....

time complexity: O(2n+n)-> O(n)
space complexity: O(2n)->O(n)

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