@ashish. The product will overflow for even moderate n, so instead, form the sum and the sum of the squares of the numbers. If a and b are the missing numbers, they satisfy
a + b = n(n+1)/2 - sum of the numbers a^2 + b^2 = n(n+1)(2n+1)/6 - sum of the squares of the numbers. Solve by the method of substitution. Dave On Aug 12, 7:50 am, ashish agarwal <ashish.cooldude...@gmail.com> wrote: > take the sum of array and product. > if they were present then sum will be n(n-1)/2 and product will be n!. > make two eq of a+b and a-b with these values and get the num > > > > On Thu, Aug 12, 2010 at 5:26 AM, vijay <auvija...@gmail.com> wrote: > > How to find two missing numbers from an unsorted continuous natural > > numbers array [only use O(1) space and O(n) time] > > > -- > > You received this message because you are subscribed to the Google Groups > > "Algorithm Geeks" group. > > To post to this group, send email to algoge...@googlegroups.com. > > To unsubscribe from this group, send email to > > algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com> > > . > > For more options, visit this group at > >http://groups.google.com/group/algogeeks?hl=en.- Hide quoted text - > > - Show quoted text - -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
