Simple run-length encoding of a ascii picture.
On 2010-9-1 3:49, Albert wrote:
#include<stdio.h>
main()
{
int a,b,c;
int count = 1;
for (b=c=10;a="- FIGURE?, UMKC,XYZHello Folks,\
TFy!QJu ROo TNn(ROo)SLq SLq ULo+\
UHs UJq TNn*RPn/QPbEWS_JSWQAIJO^\
NBELPeHBFHT}TnALVlBLOFAkHFOuFETp\
HCStHAUFAgcEAelclcn^r^r\\tZvYxXy\
T|S~Pn SPm SOn TNn ULo0ULo#ULo-W\
Hq!WFs XDt!" [b+++21]; )
This is the encoding of the picture, each charactor ch > 64 (from the
32nd byte, ie. the second row)
represent the length of a sequence of '!' or ' '. (len = ch - 64)
for(; a--> 64 ; )
putchar ( ++c=='Z' ? c = c/ 9:33^b&1);
print a sequence of '!' (if b is even) or ' '(if b is odd) with length
(a-64), beginning with sequence of ' ' (b=11),
and alternatively output sequence of '!' and sequence of ' '.
c controls the line wrap by increase from 10 to 90, then rewind to 10
and output a linefeed,
so exactly 80 bytes on each line.
return 0;
}
It just contains two for loop but i cant understand the how it is
working???
help me please.........
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