yes ..19 is the correct answer. p(f1) / \ p1 p (f2) (f2) / \ / \ / \ / \ p2 p1 p11 p(f3) (f4) (f3) (f4) /\ / \ /\ /\ / \ / \ / \ / \ / \ p3 p2 p6 p1 f5 f5 f4 f5 and so on if fork2 returns zero then fork3 is not executed.
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