@ Narsimha Raju : yes only one  such can element exit...
@Pre :
 Is there any algorithm to find median or mode in o(n)...
  because common approach are :

Find the Median of: 9, 3, 44, 17, 15 (Odd amount of numbers)
Line up your numbers: 3, 9, 15, 17, 44 (smallest to largest)
The Median is: 15 (The number in the middle)

Find the mode of:
9, 3, 3, 44, 17 , 17, 44, 15, 15, 15, 27, 40, 8,
Put the numbers is order for ease:
3, 3, 8, 9, 15, 15, 15, 17, 17, 27, 40, 44, 44,
The Mode is 15 (15 occurs the most at 3 times)....

On Wed, Sep 22, 2010 at 8:01 AM, Narsimha Raju <cnarsimhar...@gmail.com>wrote:

> @coolfrogs: How can more than one element exist of 2n/3 times repeated..
> @dave: can u add that for loop and send as i tried but could not succeed
>
> On Wed, Sep 22, 2010 at 6:23 PM, coolfrog$ <
> dixit.coolfrog.div...@gmail.com> wrote:
>
>> solution in o(n log n)
>>  can be ( as if solution exit only one element cam be a majority element
>> in the given array)
>> 1. sort the array in O(nlogn)
>> 2.  x = a[2n/3]
>>       if(a[0]==x)
>>           {  if(x== a[(2n/3])+1)
>>                 return (x)
>>
>>           }
>> On Wed, Sep 22, 2010 at 5:53 AM, Dave <dave_and_da...@juno.com> wrote:
>>
>>> Try something like this:
>>>
>>> int FindMajority( int n , int a[] )
>>> {
>>>    int majority = a[0];
>>>    int count = 1;
>>>    for( i = 1 ; i < n ; ++i )
>>>    {
>>>        if( a[i] == majority )
>>>        {
>>>            ++count;
>>>        }
>>>        else
>>>        {
>>>            if( count == 0 )
>>>            {
>>>                 majority = a[i];
>>>                 count = 1;
>>>            }
>>>            else
>>>            {
>>>                 --count;
>>>            }
>>>        }
>>>    }
>>>    return majority;
>>> }
>>>
>>> It will find an element that occurs at least n/2 times in the array.
>>> If you need to verify that the element occurs 2n/3 times, add a loop
>>> to count the number of occurences of majority before the return.
>>>
>>> On Sep 21, 10:42 pm, pre <pre.la...@gmail.com> wrote:
>>> > Hi all,
>>> > pls help me solve this problem..
>>> > Design an algorithm to find the majority element of an array..
>>> > majority element must be an element tht has the cardinality greater
>>> > than 2n/3 where n is the number of elements in the array and the time
>>> > complexity must be a linear time.. ie o(n)..
>>> >
>>> > hint : use mode or median to solve ..
>>>
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>
>
>
> --
> Regards,
> C. Narsimha Raju
> MS, IIIT Hyderabad.
> http://research.iiit.ac.in/~narsimha_raju/<http://research.iiit.ac.in/%7Enarsimha_raju/>
>
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