@Akarsh.
for inserting only,we need a new node and it is not possible without having
new pointer(we have to ref. the new node with some pointer.) once insertion
complete, we left with one pointer which point to old node.
swapping can be done with 1 pointer only,if nodes are adjacent(in this
case).
Rahul.
On Thu, Oct 7, 2010 at 1:05 PM, Akarsh D <taged...@gmail.com> wrote:
> @Rahul : I think the swapping method will work. But still have to use two
> pointers.
>
> On Thu, Oct 7, 2010 at 12:34 AM, sajj <sajjv...@gmail.com> wrote:
>
>> In a single linked list its is not at all possible i hope correct me
>> if im wrong ... with given one pointer and with out knowing where head
>> is.. even if u know the position of the head it ll help you out for
>> arriving the solution if and only if it is pointing to any of the
>> following nodes 1 or 2 or 3
>>
>> On Oct 6, 10:56 pm, shoban babu <bsbabu...@gmail.com> wrote:
>> > @Rahul
>> > the only one pointer is there and it is pointing to the 4th node only,,
>> and
>> > we don't know where the head is points to...
>> >
>> > On Wed, Oct 6, 2010 at 11:20 PM, RAHUL KUJUR <kujurismonu2...@gmail.com
>> >wrote:
>> >
>> >
>> >
>> > > Take two pointers p and q. Initially p points to head.
>> >
>> > > while(p!="given pointer")
>> > > {
>> > > p=p->link;
>> > > q=p;
>> > > };
>> >
>> > > Now you hv pointer at 3rd and 4th position. Now insertion is
>> simple....Hope
>> > > this will work
>> >
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>> > Shoban babu.B
>> > M.E.,CSA,
>> > IISc.
>>
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