I think this pasted code is incorrect ... answer for { 2, 5, 7, 1, 8, 9 }
should be 18, right?

On Thu, Oct 7, 2010 at 10:53 PM, Anand <anandut2...@gmail.com> wrote:

> Using standard Dynamic Programing logic:
> http://codepad.org/IwBTor4F
>
>
>
> On Thu, Oct 7, 2010 at 8:43 PM, Gene <gene.ress...@gmail.com> wrote:
>
>> Nice problem.  Let N_1, N_2, ... N_n be the values of the N notes.
>> Let F(i,j) be the maximum possible score the current player can get
>> using only notes i through j.  Then
>>
>> F(i,j) = sum_{k = i to j}N_k - min( F(i+1, j), F(i, j-1) )
>>
>> This is saying that the current player always makes the choice that
>> minimizes B the best score that the other player can achieve.  When we
>> know that choice, the best _we_ can do is the sum of all the available
>> notes minus B.
>>
>> The base case is F(k,k) = N_k, and we are unconcerned with F(i,j)
>> where i > j.
>>
>> For example, suppose we have notes 3 7 2 1 .  The answer we want is
>> F(1,4).
>>
>> Initially we have
>> F(1,1) = 3
>> F(2,2) = 7
>> F(3,3) = 2
>> F(4,4) = 1
>>
>> Now we can compute
>> F(1,2) = 10 - min(F(2,2), F(1,1)) = 10 - min(7,3) = 7 (pick N_1=7).
>> F(2,3) =  9 - min(F(3,3), F(2,2)) =  9 - min(2,7) = 7 (pick N_2=7).
>> F(3,4) =  3 - min(F(4,4), F(3,3)) =  3 - min(1,2) = 2 (pick N_3=2).
>> F(1,3) = 12 - min(F(2,3), F(1,2)) = 12 - min(7,7) = 5 (don't care).
>> F(2,4) = 10 - min(F(3,4), F(2,3)) = 10 - min(2,7) = 8 (pick N_2=7).
>> F(1,4) = 13 - min(F(2,4), F(1,3)) = 13 - min(8,5) = 8 (pick N_4=1).
>>
>>
>> On Oct 7, 8:14 pm, Anand <anandut2...@gmail.com> wrote:
>> > Given a row of notes (with specified values), two players play a game.
>> At
>> > each turn, any player can pick a note from any of the two ends. How will
>> the
>> > first player maximize his score? Both players will play optimally.
>>
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