Here is the modified code. Maybe we can find something new.
Code:
#include<stdio.h>
int main()
{
union {
struct {
int x;
float t;
};
double u;
} a;
a.x=0;
scanf("%f",&a.t);
printf("%f\n",a.t);
printf("%f\n",a.u);
a.x=90;
printf("%d\n",a.x);
printf("%f\n",a.x);
printf("%f\n",a.t);
printf("%f\n",a.u);
a.x=1;
printf("%d\n",a.x);
printf("%f\n",a.x);
printf("%f\n",a.t);
printf("%f\n",a.u);
a.x=30;
printf("%d\n",a.x);
printf("%f\n",a.x);
printf("%f\n",a.t);
printf("%f\n",a.u);
a.x=9;
printf("%d\n",a.x);
printf("%f\n",a.x);
printf("%f\n",a.t);
printf("%f\n",a.u);
return 0;
}
Input: 3
Output:
3.000000
32.000000
90
32.000000
3.000000
32.000000
1
32.000000
3.000000
32.000000
30
32.000000
3.000000
32.000000
9
32.000000
3.000000
32.000000
Input: 32
Output:
32
32.000000
8589934592.000000
90
8589934592.000172
32.000000
8589934592.000172
1
8589934592.000002
32.000000
8589934592.000002
30
8589934592.000057
32.000000
8589934592.000057
9
8589934592.000017
32.000000
8589934592.000017
On 2010-10-11 2:06, Asquare wrote:
As far as I have understood.. Its basically that
once you give the input to t as float, that value is displayed for all
the printf functions except one
because of the %f modifier.. the %f modifier cannot accept x (int) as
a successful argument so it takes the
latest float value..
but in case of
x=30;
printf("%d\n",x);
this printf has %d as modifier so the output is 30.
say t entered is 43.5
so OUTPUT: (as per gcc compiler)
43.5
43.5
43.5
30
43.5
43.5
correct me if im wrong..
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