Read the question again..only 3rd case you have mentioned needs t

On Wed, Oct 13, 2010 at 12:58 PM, Shiyam code_for_life <
mailshyamh...@gmail.com> wrote:

> First lets look at how many ways the array can be split
> (1) 1,7
> (2) 2,6o be considered here...
> (3) 3,5
> (4) 4,4
>
> Now how many combinations in each
>
> 1,7 => 8 combinations for first array
> 2,6 => 8*7 combinations for first array
> 3,5 => 8*7*6 combinations for first array
> 4,4 => 8*7*6*5 combinations for first array
>
> so its the sum (8) + (8*7) + (8*7*6) + (8*7*6*5)
>
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