oh ya thanks now i got it

On Sun, Oct 24, 2010 at 9:54 AM, preetika tyagi <preetikaty...@gmail.com>wrote:

> @Praveen- In this case, we will not ignore the right subtree of the root
> (-10, which is less than zero) while traversing the tree.
>
>
> On Sat, Oct 23, 2010 at 9:06 PM, Praveen Baskar 
> <praveen200...@gmail.com>wrote:
>
>> i think it is possible nishaanth
>> please do take a look at this example
>>
>>                         -10
>>                        /    \
>>                      -11   8
>>                             /\
>>                           -5 10
>>      -5 is greater than -10
>>
>>
>> On Sat, Oct 23, 2010 at 11:19 PM, nishaanth <nishaant...@gmail.com>wrote:
>>
>>> @Praveen....it is not possible..in a BST *all the nodes* on the right
>>> subtree are greater than the node :)
>>>
>>>
>>> On Sat, Oct 16, 2010 at 3:26 PM, Praveen Baskar <praveen200...@gmail.com
>>> > wrote:
>>>
>>>> @nishaanth: wat if the left child of the right node has a negative value
>>>>
>>>>
>>>> On Thu, Oct 14, 2010 at 11:12 AM, nishaanth <nishaant...@gmail.com>wrote:
>>>>
>>>>>
>>>>>
>>>>>> Just see the value of the node at every point, if it is greater than
>>>>> zero dont recurse the right sub-tree, as simple as it is.print the node u
>>>>> inspected if it is less than zero.
>>>>>
>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> S.Nishaanth,
>>>>> Computer Science and engineering,
>>>>> IIT Madras.
>>>>>
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>>
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