1) There are 4 columns: {1,3}, {5,7}, {2,4}, {6,8};
2) Column {1,3} and {6,8} must be in the middle, while column {2,4}
besides {6,8}, and {5,7} besides {1,3}
3) The 2 numbers in each column can be swapped freely.
So there are 32 solutions in total.
On 2010-11-12 11:18, Amod wrote:
Gr8, guys :)
If any body can formalize the solution, then it would be great
On Nov 12, 12:17 am, Shiv Shankar Prajapati
<mca.shivshan...@gmail.com> wrote:
Several solutions are possible for it
5 1 8 2
7 3 6 4
Here we can swap the position of 5<->7, 1<->3 etc.
On Thu, Nov 11, 2010 at 11:48 PM, jagannath prasad das
<jpdasi...@gmail.com>wrote:
4 8 3 7
2 6 1 5
On Thu, Nov 11, 2010 at 5:57 PM, sunny agrawal<sunny816.i...@gmail.com>wrote:
@rohit
4 5 are diagonally adjacent .....
On Thu, Nov 11, 2010 at 5:09 PM, Rohit Singhal<rsinghal.it...@gmail.com>wrote:
1 5 2 6
- - - - - -
3 7 4 8
On Thu, Nov 11, 2010 at 3:16 PM, Abhilasha jain<
mail2abhila...@gmail.com> wrote:
solution is
5 1 6 2
_ _ _ _
7 3 8 4
On Thu, Nov 11, 2010 at 1:26 PM, Amod<gam...@gmail.com> wrote:
We have a rectangle
It is divided in eight parts by three vertical and one horizontal line
so that there are 8 chambers.
Now we have numbers from 1-8 to be filled in these chambers.
Rule : No two consecutive numbers must be present either side to side
or diagonal
Invalid situation example
Given 5 at position 2 then 4 cannot occur at any of the give position.
4 5 4
_ _ _ _
4 4 4
_ _ _ _
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With Regards,
Shiv Shankar,
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