@coolfrog
the question never asked u to find thm in order of thier distances.
Correct me if i m wrong!

find the distances in O(n)

now using the partitioning process of quicksort.
Dividing the array into two parts:
Now if the Length of the first part is less than or equal to i we have to
now make our search into one of the subarrays

In average:
T(n)=T(n/2)+O(n)

which satisfies T(n)=O(n)

though in worst case this algorithm can take u to O(n^2)
but in average case it takes u to O(n)

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