the evalution will be done from right to left in printf
statement..........so ++x will be evaluted and then x++.....may be the out
put is 6 and 6 i think
On 13 December 2010 22:39, siva viknesh <sivavikne...@gmail.com> wrote:
> #include<stdio.h>
> int main()
> {
> int x = 5;
> printf("%d %d", x++, ++x);
>
> return 0;
>
> }
>
> for this output is "6 7" ... how evaluation proceeds??
>
> --
> Regards,
> $iva
>
> --
> You received this message because you are subscribed to the Google Groups
> "Algorithm Geeks" group.
> To post to this group, send email to algoge...@googlegroups.com.
> To unsubscribe from this group, send email to
> algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com>
> .
> For more options, visit this group at
> http://groups.google.com/group/algogeeks?hl=en.
>
--
You received this message because you are subscribed to the Google Groups
"Algorithm Geeks" group.
To post to this group, send email to algoge...@googlegroups.com.
To unsubscribe from this group, send email to
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.
