we can use DP to solve this:
dp[i][j] = coins[i][j] + max ( dp[i-1][j] , dp[i][j-1] )


On Tue, Dec 14, 2010 at 7:24 PM, divya <sweetdivya....@gmail.com> wrote:

> A table composed of N x M cells, each having a certain quantity of
> coins. You start from the upper-left corner. At each step you can go
> down or right one cell. Find the maximum number of coins you can
> collect.
>
> Provide an algorithm of O(n^2) solution.................
>
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