A[i]=A+i;
so 3.
On Thu, Dec 16, 2010 at 5:25 PM, UMESH KUMAR <kumar.umesh...@gmail.com> wrote:
>
> main()
>>>
>>> {
>>> int a[5]={1,3,6,7,0};
>>> int *b;
>>> b=&a[2];
>>> cout<<b[-1];
>>> }
>>>
>>> the value of b[-1] is
>>> a.1
>>> b.3
>>> c.-6
>>> d.none
>>>
>
> ANS will be 3.
> Because Compiler internally first converted in the form as *(b-1) , and get
> the one position back at the position 3.
>
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