On Sun, Dec 19, 2010 at 2:36 AM, Dave <dave_and_da...@juno.com> wrote:

> For 32-bit integers:
>
> x = ((x >> 16) & 0X0000FFFF) | ((x & 0X0000FFFF) << 16);
> x = ((x >>  8) & 0X00FF00FF) | ((x & 0X00FF00FF) <<  8);
> x = ((x >>  4) & 0X0F0F0F0F) | ((x & 0X0F0F0F0F) <<  4);
> x = ((x >>  2) & 0X33333333) | ((x & 0X33333333) <<  2);
> x = ((x >>  1) & 0X55555555) | ((x & 0X55555555) <<  1);
>

----->> Can U please explain the logic of this code ?

>
> x is now the binary reversal of its original value.
>
> Dave
>
> On Dec 18, 1:28 pm, Ankur Khurana <ankur.kkhur...@gmail.com> wrote:
> > you mean reverse or make 1 to 0 or 0 to 1 ?
> >
> >
> >
> > On Sun, Dec 19, 2010 at 12:52 AM, bittu <shashank7andr...@gmail.com>
> wrote:
> > > Write an Efficient C Program to Reverse Bits of a Number
> >
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-- 
Pratik Kathalkar
CoEP
BTech IT
8149198343

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