However, initial value of d should be profit of position id.
There is a case when there is an optimal way not to take any
restaurants to the right of id position, only current is enough.
Consider, the following case:
m = {1, 2}
p = {1, 4};
k = 10;
right answer is 4, not 1 :).

Also optimal solution doesn't always include first restraunt.
I think the best way to use iterative version (bottom-up approach) of the 
DP.

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