hi all, Is there a way to find a formula for the nth element of a linear recurrence ? Instead of going linearly one by one,,,, c1, c2, c3 are the three constants. a(n+3) = c1*a(n+2) - c2*a(n+1) + c3*a(n)
thanks. shady -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
