technically, malloc(25*sizeof(char)) or so would have been right ... here
malloc(25) assigns just 25 bytes as against the requirement...
On Tue, Jan 11, 2011 at 11:10 PM, UTKARSH SRIVASTAV <usrivastav...@gmail.com
> wrote:
> no nothing is wrong i have run it on my computer
>
>
>
> On Tue, Jan 11, 2011 at 9:09 AM, snehal jain <learner....@gmail.com>wrote:
>
>> sorry that was typing error.. anything else wrong except that? as it seems
>> correct to me...
>>
>>
>> On Tue, Jan 11, 2011 at 10:31 PM, Arpit Sood <soodfi...@gmail.com> wrote:
>>
>>> its correct, only a comma is missing in printf line:
>>> printf("%s",p);
>>>
>>>
>>> On Tue, Jan 11, 2011 at 10:14 PM, snehal jain <learner....@gmail.com>wrote:
>>>
>>>> what is the wrong in the program?
>>>>
>>>> main()
>>>> {
>>>> char *p,*q;
>>>> p=(char *)malloc(25);
>>>> q=(char *)malloc(25);
>>>> strcpy(p,"amazon");
>>>> strcpy(q,"hyd");
>>>> strcat(p,q);
>>>> printf("%s"p);
>>>> }
>>>>
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>>>
>>>
>>> --
>>> Arpit Sood
>>> Some day you will see things my way.
>>> http://arpit-sood.blogspot.com
>>>
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>
>
>
> --
> UTKARSH SRIVATAV
> CSE-3
> B-TECH 2nd YEAR
>
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Best,
T Anand Karthik,
Contact number: +91-9571552652
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