O(2^n)
On Sat, Jan 22, 2011 at 8:58 PM, Decipher <ankurseth...@gmail.com> wrote:
> fun(n)
> {
> if(n<=2)
> return (1);
> else
> return ((fun(n-1)*fun(n-2));
> }
>
> find the order of complexity .
>
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