@above
How can you calculate dp[n][0] with above recursive eq??

On Jan 23, 5:40 pm, sankalp srivastava <richi.sankalp1...@gmail.com>
wrote:
> @ above
> In that case  , it will be a simple dynamic programming based
> recursion
>
> assuming the total distance one has to cover is n ;
> d[i][j]=minimum number of fuel stations to stop at in order to cross i
> stations and with j miles still to go .
> dp[n][0]= minimum number of fuel stations to stop at in order cross n
> stations and with 0 miles still to go (Assuming the nth stop coincides
> with the destination B .In case it does not , we can answer something
> like dp[n][p]  , where p is the distance to go from nth stop to A)
>
> The recursion
> dp[i][k]= min(dp[i+1][k- distance b/w the ith and (i+1)th fuel
> station] , dp[i+1][k- distance +lk]+1)(lk= distance we can cover on
> this stop)
>
> base case dp[0][j]=0;(for each j )// we have to cover no more stations
> therefore
>
> On Jan 22, 9:40 pm, Divya Jain <sweetdivya....@gmail.com> wrote:
>
> > if u can take only a certain amount of fuel from a particaular station ie
> > station xi can provide li amoutn of fuel.. then wat?
>
> > On 22 January 2011 13:46, Terence <technic....@gmail.com> wrote:
>
> > > Greedy-Approach.
> > > Refueling only when you have to.
>
> > > On 2011-1-22 15:59, snehal jain wrote:
>
> > >> Suppose you want to travel from city A to city B by car, following a
> > >> fixed route. Your car can travel m miles on a full tank of gas, and
> > >> you have a map of the n gas stations on the route between A and B that
> > >> gives the number of miles between each station.
> > >> Design an algorithm to find a way to get from A to B without running
> > >> out of gas that minimizes the total number of refueling stops, in O(n)
> > >> time.
>
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